The element with the lowest atomic number tha | vedclass

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(C) The general electronic configuration for the $d$-block elements is $(n - 1)d^{1-10} ns^{1-2}$.For the configuration $(n - 1)d^6 ns^2$,the lowest p

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fourth period

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(C) The general electronic configuration for the $d$-block elements is $(n - 1)d^{1-10} ns^{1-2}$.For the configuration $(n - 1)d^6 ns^2$,the lowest possible value for the principal quantum number $n$ is $4$,because the $d$-subshell starts from $n = 3$ (i.e.,$3d$ orbital).Substituting $n = 4$ into the configuration gives $3d^6 4s^2$,which corresponds to the element Iron ($Fe$,atomic number $26$).Since $n = 4$,the element is located in the fourth period of the periodic table.

The element with the lowest atomic number that has a ground state electronic configuration of $(n - 1)d^6 ns^2$ is located in the

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